95. The equilibrium point of the reaction
CH3.CO.COOH + NADH + H+ « CH3.CHOH.COOH + NAD+
is shifted to the left by:
1. increasing the
concentration
of the enzyme catalysing the reaction
2. decreasing the
concentration
of the enzyme catalysing the reaction
3. increasing the
concentration
of CH3.CO.COOH
4. decreasing the
concentration
of H+
5. decreasing the
concentration
of NAD+
96. The equilibrium point of the reaction
is shifted to the right by:
1. increasing the
concentration
of the enzyme catalysing the reaction
2. decreasing the
concentration
of the enzyme catalysing the reaction
3. increasing the
concentration
of H+
4. decreasing the
concentration
of CH3.CHO
5. decreasing the
concentration
of NAD+
97. For the equilibrium reaction A « B + C, which one of the following is FALSE?
1. The rate of the forward
reaction is kf.[A]
2. The rate of the backward
reaction is kb.[B].[C]
3. At equilibrium kf.[A]
= kb.[B].[C] = 0
4. The rate constant kf
can be measured in min-1
5. The rate constant kb
can be measured in M-1 .min-1
98. With regard to the reaction
k-1 | |||
A | « | B + C - heat | |
k+1 |
1. The rate of the
reaction
from left to right is k+1×[A]
2. The rate of the reaction
from right to left is k-1×[B]
× [C]
3. At equilibrium k+1
= k-1
4. The equilibrium constant
Keq=
[B]× [C]¸ [A] at equilibrium
5. As temperature increases
the equilibrium point moves to the right
99. For the equilibrium
k-1 | |||
A + B | « | C + D + HEAT | |
k+1 |
1. The rate of the forward
reaction is represented by k+1.
2. The equilbrium constant
(Keq) = [C].[D] at equilibrium.
[A].[B]
3. An increase in temperature
moves the equilibrium to the left.
4. Addition of extra compound
A results in an increase in products C and D.
5. Removal of product D
results
in an increase in C.
100. With regard to the reaction:
k-1 | |||
A + B+ | « | P + Q + H+ | |
k+1 |
1. The rate of the forward
reaction is k+1×[A]× [B+]
2. The rate of the back
reaction
is k-1×[P]× [Q]× [H+]
3. As pH increases the
concentrations
of P and Q at equilibrium increase
4. The equilibrium constant
Keq
= k+1-k-1
5. The units of Keq
are for example nmol/l
101. With regard to the reaction:
k-1 | ||
A + B + H+ | « | P + Q |
k+1 |
1. The rate of the forward
reaction is k+1×[A]× [B]× [H+]
2. The rate of the back
reaction
is k-1×[P]×
[Q]
3. At equilibrium the rates
of the forward and back reactions are equal
4. The equilibrium constant
Keq
= [P]× [Q]/[A]× [B]× [H+] at
equilibrium
5. As pH increases the
concentrations
of P and Q at equilibrium increase
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